(X-2)(4x+1)-(2x+3)^2=8

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Solution for (X-2)(4x+1)-(2x+3)^2=8 equation: 



(X-2)(4X+1)-(2X+3)^2=8

We move all terms to the left:

(X-2)(4X+1)-(2X+3)^2-(8)=0

We multiply parentheses ..

(+4X^2+X-8X-2)-(2X+3)^2-8=0

We get rid of parentheses

4X^2+X-8X-(2X+3)^2-2-8=0

We add all the numbers together, and all the variables

4X^2-7X-(2X+3)^2-10=0

We move all terms containing X to the left, all other terms to the right

4X^2-7X-(2X+3)^2=10

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